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std::basic_string::capacity(3) | C++ Standard Libary | std::basic_string::capacity(3) |
NAME¶
std::basic_string::capacity - std::basic_string::capacity
Synopsis¶
size_type capacity() const; (noexcept since C++11)
(constexpr since C++20)
Returns the number of characters that the string has currently allocated
space for.
Parameters¶
(none)
Return value¶
Capacity of the currently allocated storage, i.e. the storage
available for storing
elements.
Complexity¶
Constant.
Notes¶
Memory locations obtained from the allocator but not available
for storing any
element are not counted in the allocated storage. Note that the null
terminator is
not an element of the std::basic_string.
Example¶
// Run this code
#include <iomanip>
#include <iostream>
#include <string>
void show_capacity(std::string const& s)
{
std::cout << std::quoted(s) << " has capacity "
<< s.capacity() << ".\n";
}
int main()
{
std::string s{"Exemplar"};
show_capacity(s);
s += " is an example string.";
show_capacity(s);
s.clear();
show_capacity(s);
std::cout << "\nDemonstrate the capacity's growth policy."
"\nSize: Capacity: Ratio:\n" << std::left;
std::string g;
auto old_cap{g.capacity()};
for (int mark{}; mark != 5; ++mark)
{
while (old_cap == g.capacity())
g.push_back('.');
std::cout << std::setw( 7) << g.size()
<< std::setw(11) << g.capacity()
<< std::setw(10) << g.capacity() /
static_cast<float>(old_cap) << '\n';
old_cap = g.capacity();
}
}
Possible output:¶
"Exemplar" has capacity 15.
"Exemplar is an example string." has capacity 30.
"" has capacity 30.
Demonstrate the capacity's growth policy.
Size: Capacity: Ratio:
16 30 2
31 60 2
61 120 2
121 240 2
241 480 2
See also¶
size returns the number of characters
length (public member function)
reserve reserves storage
(public member function)
2024.06.10 | http://cppreference.com |