std::swap_ranges(3) | C++ Standard Libary | std::swap_ranges(3) |
NAME¶
std::swap_ranges - std::swap_ranges
Synopsis¶
Defined in header <algorithm>
template< class ForwardIt1, class ForwardIt2 >
ForwardIt2 swap_ranges( ForwardIt1 first1, ForwardIt1 (1) (constexpr
since C++20)
last1,
ForwardIt2 first2 );
template< class ExecutionPolicy,
class ForwardIt1, class ForwardIt2 >
ForwardIt2 swap_ranges( ExecutionPolicy&& policy, (2)
(since C++17)
ForwardIt1 first1, ForwardIt1
last1,
ForwardIt2 first2 );
1) Exchanges elements between range [first1, last1) and another range of
std::distance(first1, last1) elements starting at first2.
2) Same as (1), but executed according to policy.
This overload participates in overload resolution only if
std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is
true. (until
C++20)
std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>>
is true. (since
C++20)
If any of the following conditions is satisfied, the behavior is
undefined:
* The two ranges overlap.
* There exists a pair of corresponding iterators iter1 and iter2 in the two
ranges
such that *iter1 is not Swappable with *iter2.
Parameters¶
first1, last1 - the first range of elements to swap
first2 - beginning of the second range of elements to swap
policy - the execution policy to use. See execution policy for details.
Type requirements¶
-
ForwardIt1, ForwardIt2 must meet the requirements of
LegacyForwardIterator.
Return value¶
Iterator to the element past the last element exchanged in the
range beginning with
first2.
Complexity¶
Exactly std::distance(first1, last1) swaps.
Exceptions¶
The overload with a template parameter named ExecutionPolicy
reports errors as
follows:
* If execution of a function invoked as part of the algorithm throws an
exception
and ExecutionPolicy is one of the standard policies, std::terminate is
called.
For any other ExecutionPolicy, the behavior is implementation-defined.
* If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Notes¶
Implementations (e.g. MSVC STL) may enable vectorization when the
iterator type
satisfies LegacyContiguousIterator and swapping its value type calls neither
non-trivial special member function nor ADL-found swap.
Possible implementation¶
template<class ForwardIt1, class ForwardIt2>
constexpr //< since C++20
ForwardIt2 swap_ranges(ForwardIt1 first1, ForwardIt1 last1, ForwardIt2
first2)
{
for (; first1 != last1; ++first1, ++first2)
std::iter_swap(first1, first2);
return first2;
}
Example¶
Demonstrates swapping of subranges from different containers.
// Run this code
#include <algorithm>
#include <iostream>
#include <list>
#include <vector>
auto print = [](auto comment, auto const& seq)
{
std::cout << comment;
for (const auto& e : seq)
std::cout << e << ' ';
std::cout << '\n';
};
int main()
{
std::vector<char> v{'a', 'b', 'c', 'd', 'e'};
std::list<char> l{'1', '2', '3', '4', '5'};
print("Before swap_ranges:\n" "v: ", v);
print("l: ", l);
std::swap_ranges(v.begin(), v.begin() + 3, l.begin());
print("After swap_ranges:\n" "v: ", v);
print("l: ", l);
}
Output:¶
Before swap_ranges:
v: a b c d e
l: 1 2 3 4 5
After swap_ranges:
v: 1 2 3 d e
l: a b c 4 5
See also¶
iter_swap swaps the elements pointed to by two iterators
(function template)
swap swaps the values of two objects
(function template)
ranges::swap_ranges swaps two ranges of elements
(C++20) (niebloid)
2024.06.10 | http://cppreference.com |