NAME¶

std::set_intersection - std::set_intersection

Synopsis¶

Defined in header <algorithm>
template< class InputIt1, class InputIt2, class OutputIt
>

OutputIt set_intersection( InputIt1 first1, InputIt1
last1, (1) (constexpr since C++20)
InputIt2 first2, InputIt2
last2,

OutputIt d_first );
template< class ExecutionPolicy,

class ForwardIt1, class ForwardIt2, class
ForwardIt3 >
ForwardIt3 set_intersection( ExecutionPolicy&& policy,
ForwardIt1 first1, (2) (since C++17)
ForwardIt1 last1,
ForwardIt2 first2,
ForwardIt2 last2,

ForwardIt3 d_first );
template< class InputIt1, class InputIt2,

class OutputIt, class Compare >
OutputIt set_intersection( InputIt1 first1, InputIt1
last1, (3) (constexpr since C++20)
InputIt2 first2, InputIt2
last2,

OutputIt d_first, Compare
comp );
template< class ExecutionPolicy,

class ForwardIt1, class ForwardIt2,
class ForwardIt3, class Compare >
ForwardIt3 set_intersection( ExecutionPolicy&& policy,
ForwardIt1 first1, (4) (since C++17)
ForwardIt1 last1,
ForwardIt2 first2,
ForwardIt2 last2,

ForwardIt3 d_first, Compare
comp );

Constructs a sorted range beginning at d_first consisting of elements that are found
in both sorted ranges [first1, last1) and [first2, last2).

If [first1, last1) contains m elements that are equivalent to each other and
[first2, last2) contains n elements that are equivalent to them, the first
std::min(m, n) elements will be copied from [first1, last1) to the output range,
preserving order.

1) If [first1, last1) or [first2, last2) is not sorted with respect to
operator<
(until C++20)
std::less{}
(since C++20), the behavior is undefined.
3) If [first1, last1) or [first2, last2) is not sorted with respect to comp, the
behavior is undefined.
2,4) Same as (1,3), but executed according to policy.
These overloads participate in overload resolution only if

std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true. (until
C++20)
std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>> is true. (since
C++20)

If the output range overlaps with [first1, last1) or [first2, last2), the behavior
is undefined.

Parameters¶

first1, last1 - the first range of elements to examine
first2, last2 - the second range of elements to examine
d_first - the beginning of the output range
policy - the execution policy to use. See execution policy for details.
comparison function object (i.e. an object that satisfies the
requirements of Compare) which returns true if the first argument is
less than (i.e. is ordered before) the second.

The signature of the comparison function should be equivalent to the
following:

bool cmp(const Type1& a, const Type2& b);
comp -
While the signature does not need to have const&, the function must
not modify the objects passed to it and must be able to accept all
values of type (possibly const) Type1 and Type2 regardless of value
category (thus, Type1& is not allowed
, nor is Type1 unless for Type1 a move is equivalent to a copy
(since C++11)).
The types Type1 and Type2 must be such that objects of types
InputIt1 and InputIt2 can be dereferenced and then implicitly
converted to both Type1 and Type2.

Type requirements¶

-
InputIt1, InputIt2 must meet the requirements of LegacyInputIterator.
-
OutputIt must meet the requirements of LegacyOutputIterator.
-
ForwardIt1, ForwardIt2, ForwardIt3 must meet the requirements of
LegacyForwardIterator.
-
Compare must meet the requirements of Compare.

Return value¶

Iterator past the end of the constructed range.

Complexity¶

Given \(\scriptsize N_1\)N
1 as std::distance(first1, last1) and \(\scriptsize N_2\)N
2 as std::distance(first2, last2):

1,2) At most \(\scriptsize 2 \cdot (N_1+N_2)-1\)2⋅(N
1+N
2)-1 comparisons using
operator<
(until C++20)
std::less{}
(since C++20).
3,4) At most \(\scriptsize 2 \cdot (N_1+N_2)-1\)2⋅(N
1+N
2)-1 applications of the comparison function comp.

Exceptions¶

The overloads with a template parameter named ExecutionPolicy report errors as
follows:

* If execution of a function invoked as part of the algorithm throws an exception
and ExecutionPolicy is one of the standard policies, std::terminate is called.
For any other ExecutionPolicy, the behavior is implementation-defined.
* If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Possible implementation¶

set_intersection (1) template<class InputIt1, class InputIt2, class OutputIt> OutputIt set_intersection(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2, OutputIt d_first) {
while (first1 != last1 && first2 != last2)
{
if (*first1 < *first2)
++first1;
else
{
if (!(*first2 < *first1))
*d_first++ = *first1++; // *first1 and *first2 are equivalent.
++first2;
}
}
return d_first; }
set_intersection (3) template<class InputIt1, class InputIt2, class OutputIt, class Compare> OutputIt set_intersection(InputIt1 first1, InputIt1 last1,
InputIt2 first2, InputIt2 last2, OutputIt d_first, Compare comp) {
while (first1 != last1 && first2 != last2)
{
if (comp(*first1, *first2))
++first1;
else
{
if (!comp(*first2, *first1))
*d_first++ = *first1++; // *first1 and *first2 are equivalent.
++first2;
}
}
return d_first; }

Example¶

// Run this code

#include <algorithm>
#include <iostream>
#include <iterator>
#include <vector>

int main()
{
std::vector<int> v1{7, 2, 3, 4, 5, 6, 7, 8};
std::vector<int> v2{5, 7, 9, 7};
std::sort(v1.begin(), v1.end());
std::sort(v2.begin(), v2.end());

std::vector<int> v_intersection;
std::set_intersection(v1.begin(), v1.end(), v2.begin(), v2.end(),
std::back_inserter(v_intersection));

for (int n : v_intersection)
std::cout << n << ' ';
std::cout << '\n';
}

Output:¶

5 7 7

Defect reports

The following behavior-changing defect reports were applied retroactively to
previously published C++ standards.

DR Applied to Behavior as published Correct behavior
LWG 291 C++98 it was unspecified how to handle equivalent specified
elements in the input ranges

See also¶

set_union computes the union of two sets
(function template)
ranges::set_intersection computes the intersection of two sets
(C++20) (niebloid)