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std::reference_wrapper::operator()(3) | C++ Standard Libary | std::reference_wrapper::operator()(3) |
NAME¶
std::reference_wrapper::operator() - std::reference_wrapper::operator()
Synopsis¶
template< class... ArgTypes >
(since C++11)
typename std::result_of<T&(ArgTypes&&...)>::type (until
C++17)
operator() ( ArgTypes&&... args ) const;
template< class... ArgTypes >
(since C++17)
std::invoke_result_t<T&, ArgTypes...> (constexpr since
C++20)
operator() ( ArgTypes&&... args ) const noexcept(/* see below
*/);
Calls the Callable object, reference to which is stored, as if by
INVOKE(get(),
std::forward<ArgTypes>(args)...). This function is available only if
the stored
reference points to a Callable object.
T must be a complete type.
Parameters¶
args - arguments to pass to the called function
Return value¶
The return value of the called function.
Exceptions¶
May throw implementation-defined exceptions. (since C++11)
(until C++17)
noexcept specification: (since C++17)
noexcept(std::is_nothrow_invocable_v<T&, ArgTypes...>)
Example¶
// Run this code
#include <functional>
#include <iostream>
void f1()
{
std::cout << "reference to function called\n";
}
void f2(int n)
{
std::cout << "bind expression called with " << n
<< " as the argument\n";
}
int main()
{
std::reference_wrapper<void()> ref1 = std::ref(f1);
ref1();
auto b = std::bind(f2, std::placeholders::_1);
auto ref2 = std::ref(b);
ref2(7);
auto c = []{ std::cout << "lambda function called\n"; };
auto ref3 = std::ref(c);
ref3();
}
Output:¶
reference to function called
bind expression called with 7 as the argument
lambda function called
Defect reports
The following behavior-changing defect reports were applied retroactively to
previously published C++ standards.
DR Applied to Behavior as published Correct behavior
LWG 3764 C++17 operator() is not noexcept propagate noexcept
See also¶
get accesses the stored reference
operator T& (public member function)
Category:¶
* conditionally noexcept
2024.06.10 | http://cppreference.com |