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std::ranges::rotate_copy,std::ranges::rotate_copy_result(3) | C++ Standard Libary | std::ranges::rotate_copy,std::ranges::rotate_copy_result(3) |
NAME¶
std::ranges::rotate_copy,std::ranges::rotate_copy_result - std::ranges::rotate_copy,std::ranges::rotate_copy_result
Synopsis¶
Defined in header <algorithm>
Call signature
template< std::forward_iterator I, std::sentinel_for<I> S,
std::weakly_incrementable O >
requires std::indirectly_copyable<I, O> (1) (since C++20)
constexpr rotate_copy_result<I, O>
rotate_copy( I first, I middle, S last, O result );
template< ranges::forward_range R, std::weakly_incrementable O >
requires std::indirectly_copyable<ranges::iterator_t<R>, O>
(2) (since C++20)
constexpr rotate_copy_result<ranges::borrowed_iterator_t<R>,
O>
rotate_copy( R&& r, ranges::iterator_t<R> middle, O result
);
Helper types¶
template< class I, class O > (3) (since
C++20)
using rotate_copy_result = in_out_result<I, O>;
1) Copies the elements from the source range [first, last), to the
destination range
beginning at result in such a way, that the element *middle becomes the first
element of the destination range and *(middle - 1) becomes the last element.
The
result is that the destination range contains a left rotated copy of the
source
range.
The behavior is undefined if either [first, middle) or [middle, last) is not
a valid
range, or the source and destination ranges overlap.
2) Same as (1), but uses r as the source range, as if using
ranges::begin(r) as
first and ranges::end(r) as last.
The function-like entities described on this page are niebloids, that is:
* Explicit template argument lists cannot be specified when calling any of
them.
* None of them are visible to argument-dependent lookup.
* When any of them are found by normal unqualified lookup as the name to the
left
of the function-call operator, argument-dependent lookup is inhibited.
In practice, they may be implemented as function objects, or with special
compiler
extensions.
Parameters¶
first, last - the source range of elements to copy from
r - the source range of elements to copy from
middle - the iterator to the element that should appear at the beginning of
the
destination range
result - beginning of the destination range
Return value¶
{last, result + N}, where N = ranges::distance(first, last).
Complexity¶
Linear: exactly N assignments.
Notes¶
If the value type is TriviallyCopyable and the iterator types
satisfy
contiguous_iterator, implementations of ranges::rotate_copy usually avoid
multiple
assignments by using a "bulk copy" function such as
std::memmove.
Possible implementation¶
See also the implementations in libstdc++ and MSVC STL.
struct rotate_copy_fn {
template<std::forward_iterator I, std::sentinel_for<I> S,
std::weakly_incrementable O>
requires std::indirectly_copyable<I, O>
constexpr ranges::rotate_copy_result<I, O>
operator()(I first, I middle, S last, O result) const
{
auto c1 {ranges::copy(middle, std::move(last), std::move(result))};
auto c2 {ranges::copy(std::move(first), std::move(middle),
std::move(c1.out))};
return {std::move(c1.in), std::move(c2.out)};
}
template<ranges::forward_range R, std::weakly_incrementable O>
requires std::indirectly_copyable<ranges::iterator_t<R>, O>
constexpr ranges::rotate_copy_result<ranges::borrowed_iterator_t<R>,
O>
operator()(R&& r, ranges::iterator_t<R> middle, O result) const
{
return (*this)(ranges::begin(r), std::move(middle),
ranges::end(r), std::move(result));
} };
inline constexpr rotate_copy_fn rotate_copy {};
Example¶
// Run this code
#include <algorithm>
#include <iostream>
#include <iterator>
#include <vector>
int main()
{
std::vector<int> src {1, 2, 3, 4, 5};
std::vector<int> dest(src.size());
auto pivot = std::ranges::find(src, 3);
std::ranges::rotate_copy(src, pivot, dest.begin());
for (int i : dest)
std::cout << i << ' ';
std::cout << '\n';
// copy the rotation result directly to the std::cout
pivot = std::ranges::find(dest, 1);
std::ranges::rotate_copy(dest, pivot,
std::ostream_iterator<int>(std::cout, " "));
std::cout << '\n';
}
Output:¶
3 4 5 1 2
1 2 3 4 5
See also¶
ranges::rotate rotates the order of elements in a range
(C++20) (niebloid)
ranges::copy
ranges::copy_if copies a range of elements to a new location
(C++20) (niebloid)
(C++20)
rotate_copy copies and rotate a range of elements
(function template)
2024.06.10 | http://cppreference.com |