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std::ranges::max_element(3) C++ Standard Libary std::ranges::max_element(3)

NAME

std::ranges::max_element - std::ranges::max_element

Synopsis


Defined in header <algorithm>
Call signature
template< std::forward_iterator I, std::sentinel_for<I> S, class Proj =
std::identity,


std::indirect_strict_weak_order<std::projected<I, Proj>> Comp = (1) (since
ranges::less > C++20)


constexpr I max_element( I first, S last, Comp comp = {}, Proj proj = {}
);
template< ranges::forward_range R, class Proj = std::identity,


std::indirect_strict_weak_order< (since
std::projected<ranges::iterator_t<R>, Proj>> Comp = ranges::less > (2) C++20)
constexpr ranges::borrowed_iterator_t<R>


max_element( R&& r, Comp comp = {}, Proj proj = {} );


1) Finds the greatest element in the range [first, last).
2) Same as (1), but uses r as the source range, as if using ranges::begin(r) as
first and ranges::end(r) as last.


The function-like entities described on this page are niebloids, that is:


* Explicit template argument lists may not be specified when calling any of them.
* None of them is visible to argument-dependent lookup.
* When one of them is found by normal unqualified lookup for the name to the left
of the function-call operator, it inhibits argument-dependent lookup.


In practice, they may be implemented as function objects, or with special compiler
extensions.

Parameters


first, last - iterator-sentinel pair denoting the range to examine
r - the range to examine
comp - comparison to apply to the projected elements
proj - projection to apply to the elements

Return value


Iterator to the greatest element in the range [first, last). If several elements in
the range are equivalent to the greatest element, returns the iterator to the first
such element. Returns first if the range is empty.

Complexity


Exactly max(N-1,0) comparisons, where N = ranges::distance(first, last).

Possible implementation


struct max_element_fn {
template<std::forward_iterator I, std::sentinel_for<I> S, class Proj = std::identity,
std::indirect_strict_weak_order<std::projected<I, Proj>> Comp = ranges::less>
constexpr I operator()(I first, S last, Comp comp = {}, Proj proj = {}) const
{
if (first == last) {
return last;
}


auto largest = first;
++first;
for (; first != last; ++first) {
if (std::invoke(comp, std::invoke(proj, *largest), std::invoke(proj, *first))) {
largest = first;
}
}
return largest;
}


template<ranges::forward_range R, class Proj = std::identity,
std::indirect_strict_weak_order<
std::projected<ranges::iterator_t<R>, Proj>> Comp = ranges::less>
constexpr ranges::borrowed_iterator_t<R>
operator()(R&& r, Comp comp = {}, Proj proj = {}) const
{
return (*this)(ranges::begin(r), ranges::end(r), std::ref(comp), std::ref(proj));
}
};


inline constexpr max_element_fn max_element;

Example

// Run this code


#include <algorithm>
#include <iostream>
#include <vector>
#include <cmath>


int main()
{
std::vector<int> v{ 3, 1, -14, 1, 5, 9 };


namespace ranges = std::ranges;
auto result = ranges::max_element(v.begin(), v.end());
std::cout << "max element at: " << ranges::distance(v.begin(), result) << '\n';


auto abs_compare = [](int a, int b) { return (std::abs(a) < std::abs(b)); };
result = ranges::max_element(v, abs_compare);
std::cout << "max element (absolute) at: " << ranges::distance(v.begin(), result) << '\n';
}

Output:


max element at: 5
max element (absolute) at: 2

See also


ranges::min_element returns the smallest element in a range
(C++20) (niebloid)
ranges::minmax_element returns the smallest and the largest elements in a range
(C++20) (niebloid)
ranges::max returns the greater of the given values
(C++20) (niebloid)
max_element returns the largest element in a range
(function template)

2022.07.31 http://cppreference.com