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| std::partition_point(3) | C++ Standard Libary | std::partition_point(3) | 
NAME¶
std::partition_point - std::partition_point
Synopsis¶
 Defined in header <algorithm>
  
   template< class ForwardIt, class UnaryPred > (since C++11)
  
   ForwardIt partition_point( ForwardIt first, ForwardIt last, (constexpr since
    C++20)
  
   UnaryPred p );
  
   Examines the partitioned range [first, last) and locates the end of the first
  
   partition, that is, the first element that does not satisfy p or last if all
  
   elements satisfy p.
  
   If the elements elem of [first, last) are not partitioned with respect to the
  
   expression bool(p(elem)), the behavior is undefined.
Parameters¶
 first, last - the partitioned range of elements to examine
  
   unary predicate which returns true for the elements found in the
  
   beginning of the range.
  
   The expression p(v) must be convertible to bool for every argument v
  
   p - of type (possibly const) VT, where VT is the value type of ForwardIt,
  
   regardless of value category, and must not modify v. Thus, a parameter
  
   type of VT&is not allowed
  
   , nor is VT unless for VT a move is equivalent to a copy
  
   (since C++11).
Type requirements¶
 -
  
   ForwardIt must meet the requirements of LegacyForwardIterator.
  
   -
  
   UnaryPred must meet the requirements of Predicate.
Return value¶
 The iterator past the end of the first partition within [first,
    last) or last if all
  
   elements satisfy p.
Complexity¶
 Given \(\scriptsize N\)N as std::distance(first, last), performs
    \(\scriptsize
  
   O(log(N))\)O(log(N)) applications of the predicate p.
Notes¶
 This algorithm is a more general form of std::lower_bound, which
    can be expressed in
  
   terms of std::partition_point with the predicate [&](const auto& e) {
    return e <
  
   value; });.
Possible implementation¶
 template<class ForwardIt, class UnaryPred>
  
   constexpr //< since C++20
  
   ForwardIt partition_point(ForwardIt first, ForwardIt last, UnaryPred p)
  
   {
  
   for (auto length = std::distance(first, last); 0 < length; )
  
   {
  
   auto half = length / 2;
  
   auto middle = std::next(first, half);
  
   if (p(*middle))
  
   {
  
   first = std::next(middle);
  
   length -= (half + 1);
  
   }
  
   else
  
   length = half;
  
   }
  
   return first;
  
   }
Example¶
// Run this code
  
   #include <algorithm>
  
   #include <array>
  
   #include <iostream>
  
   #include <iterator>
  
   auto print_seq = [](auto rem, auto first, auto last)
  
   {
  
   for (std::cout << rem; first != last; std::cout << *first++
    << ' ') {}
  
   std::cout << '\n';
  
   };
  
   int main()
  
   {
  
   std::array v{1, 2, 3, 4, 5, 6, 7, 8, 9};
  
   auto is_even = [](int i) { return i % 2 == 0; };
  
   std::partition(v.begin(), v.end(), is_even);
  
   print_seq("After partitioning, v: ", v.cbegin(), v.cend());
  
   const auto pp = std::partition_point(v.cbegin(), v.cend(), is_even);
  
   const auto i = std::distance(v.cbegin(), pp);
  
   std::cout << "Partition point is at " << i <<
    "; v[" << i << "] = " << *pp <<
    '\n';
  
   print_seq("First partition (all even elements): ", v.cbegin(), pp);
  
   print_seq("Second partition (all odd elements): ", pp, v.cend());
  
   }
Possible output:¶
 After partitioning, v: 8 2 6 4 5 3 7 1 9
  
   Partition point is at 4; v[4] = 5
  
   First partition (all even elements): 8 2 6 4
  
   Second partition (all odd elements): 5 3 7 1 9
See also¶
 find
  
   find_if finds the first element satisfying specific criteria
  
   find_if_not (function template)
  
   (C++11)
  
   is_sorted checks whether a range is sorted into ascending order
  
   (C++11) (function template)
  
   returns an iterator to the first element not less than the
  
   lower_bound given value
  
   (function template)
  
   ranges::partition_point locates the partition point of a partitioned range
  
   (C++20) (niebloid)
| 2024.06.10 | http://cppreference.com |