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| std::numeric_limits::lowest(3) | C++ Standard Libary | std::numeric_limits::lowest(3) | 
NAME¶
std::numeric_limits::lowest - std::numeric_limits::lowest
Synopsis¶
static constexpr T lowest() noexcept; (since C++11)
  
   Returns the lowest finite value representable by the numeric type T, that is,
    a
  
   finite value x such that there is no other finite value y where y < x.
    This is
  
   different from std::numeric_limits<T>::min() for floating-point types.
    Only
  
   meaningful for bounded types.
Return value¶
 T std::numeric_limits<T>::lowest()
  
   /* non-specialized */ T()
  
   bool false
  
   char CHAR_MIN
  
   signed char SCHAR_MIN
  
   unsigned char 0
  
   wchar_t WCHAR_MIN
  
   char8_t (since C++20) 0
  
   char16_t 0
  
   char32_t 0
  
   short SHRT_MIN
  
   unsigned short 0
  
   int INT_MIN
  
   unsigned int 0
  
   long LONG_MIN
  
   unsigned long 0
  
   long long LLONG_MIN
  
   unsigned long long 0
  
   float -FLT_MAX
  
   double -DBL_MAX
  
   long double -LDBL_MAX
Notes¶
 For every standard C++ floating-point type T
    std::numeric_limits<T>::lowest() ==
  
   -std::numeric_limits<T>::max(), but this does not necessarily have to
    be the case
  
   for any third-party specialization.
Example¶
Demonstrates min(), max(), and lowest() for floating-point types:
// Run this code
  
   #include <iostream>
  
   #include <limits>
  
   #include <string_view>
  
   template<typename T>
  
   void print_twice(std::string_view type, T value)
  
   {
  
   std::cout << '\t' << type << ": "
  
   << std::defaultfloat << value << " or "
  
   << std::hexfloat << value << '\n';
  
   }
  
   int main()
  
   {
  
   // min()
  
   std::cout << "std::numeric_limits<T>::min():\n";
  
   print_twice("float", std::numeric_limits<float>::min());
  
   print_twice("double", std::numeric_limits<double>::min());
  
   print_twice("long double", std::numeric_limits<long
    double>::min());
  
   // lowest()
  
   std::cout << "std::numeric_limits<T>::lowest():\n";
  
   print_twice("float", std::numeric_limits<float>::lowest());
  
   print_twice("double", std::numeric_limits<double>::lowest());
  
   print_twice("long double", std::numeric_limits<long
    double>::lowest());
  
   // max()
  
   std::cout << "std::numeric_limits<T>::max():\n";
  
   print_twice("float", std::numeric_limits<float>::max());
  
   print_twice("double", std::numeric_limits<double>::max());
  
   print_twice("long double", std::numeric_limits<long
    double>::max());
  
   }
Output:¶
 std::numeric_limits<T>::min():
  
   float: 1.17549e-38 or 0x1p-126
  
   double: 2.22507e-308 or 0x1p-1022
  
   long double: 3.3621e-4932 or 0x8p-16385
  
   std::numeric_limits<T>::lowest():
  
   float: -3.40282e+38 or -0x1.fffffep+127
  
   double: -1.79769e+308 or -0x1.fffffffffffffp+1023
  
   long double: -1.18973e+4932 or -0xf.fffffffffffffffp+16380
  
   std::numeric_limits<T>::max():
  
   float: 3.40282e+38 or 0x1.fffffep+127
  
   double: 1.79769e+308 or 0x1.fffffffffffffp+1023
  
   long double: 1.18973e+4932 or 0xf.fffffffffffffffp+16380
See also¶
 min returns the smallest finite value of the given type
  
   [static] (public static member function)
  
   denorm_min returns the smallest positive subnormal value of the given
    floating-point
  
   [static] type
  
   (public static member function)
  
   max returns the largest finite value of the given type
  
   [static] (public static member function)
| 2024.06.10 | http://cppreference.com |