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| std::literals::chrono_literals::operator""us(3) | C++ Standard Libary | std::literals::chrono_literals::operator""us(3) | 
NAME¶
std::literals::chrono_literals::operator""us - std::literals::chrono_literals::operator""us
Synopsis¶
 Defined in header <chrono>
  
   constexpr std::chrono::microseconds (1) (since C++14)
  
   operator""us( unsigned long long us );
  
   constexpr std::chrono::duration</*unspecified*/, std::micro> (2)
    (since C++14)
  
   operator""us( long double us );
  
   Forms a std::chrono::duration literal representing microseconds.
  
   1) Integer literal, returns exactly std::chrono::microseconds(us).
  
   2) Floating-point literal, returns a floating-point duration equivalent to
  
   std::chrono::microseconds.
Parameters¶
us - the number of microseconds
Return value¶
The std::chrono::duration literal.
Possible implementation¶
 constexpr std::chrono::microseconds
    operator""us(unsigned long long us)
  
   {
  
   return std::chrono::microseconds(us);
  
   }
  
   constexpr std::chrono::duration<long double, std::micro>
    operator""us(long double us)
  
   {
  
   return std::chrono::duration<long double, std::micro>(us);
  
   }
Notes¶
 This operator is declared in the namespace
    std::literals::chrono_literals, where
  
   both literals and chrono_literals are inline namespaces. Access to this
    operator can
  
   be gained with:
  
   * using namespace std::literals,
  
   * using namespace std::chrono_literals, or
  
   * using namespace std::literals::chrono_literals.
  
   In addition, within the namespace std::chrono, the directive using namespace
  
   literals::chrono_literals; is provided by the standard library, so that if a
  
   programmer uses using namespace std::chrono; to gain access to the classes in
    the
  
   chrono library, the corresponding literal operators become visible as
  well.
Example¶
// Run this code
  
   #include <chrono>
  
   #include <iostream>
  
   int main()
  
   {
  
   using namespace std::chrono_literals;
  
   auto d1 = 250us;
  
   std::chrono::microseconds d2 = 1ms;
  
   std::cout << d1 << " = " << d1.count() <<
    " microseconds\n"
  
   << 1ms << " = " << d2.count() << "
    microseconds\n";
  
   }
Output:¶
 250us = 250 microseconds
  
   1ms = 1000 microseconds
See also¶
 constructor constructs new duration
  
   (public member function of
  std::chrono::duration<Rep,Period>)
| 2024.06.10 | http://cppreference.com |