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std::indirectly_writable(3) C++ Standard Libary std::indirectly_writable(3)

NAME

std::indirectly_writable - std::indirectly_writable

Synopsis


Defined in header <iterator>
template< class Out, class T >


concept indirectly_writable =
requires(Out&& o, T&& t) {
*o = std::forward<T>(t);
*std::forward<Out>(o) = std::forward<T>(t);
const_cast<const std::iter_reference_t<Out>&&>(*o) = (since
std::forward<T>(t); C++20)
const_cast<const
std::iter_reference_t<Out>&&>(*std::forward<Out>(o)) =
std::forward<T>(t);
};


/* none of the four expressions above are required to be
equality-preserving */


The concept indirectly_writable<Out, T> specifies the requirements for writing a
value whose type and value category are encoded by T into an iterator Out's
referenced object.


Semantic requirements


Let e be an expression such that decltype((e)) is T, and o be a dereferenceable
object of type Out, then indirectly_writable<Out, T> is modeled only if:


* If std::indirectly_readable<Out> is modeled and std::iter_value_t<Out> is the
same type as std::decay_t<T>, then *o after any above assignment is equal to the
value of e before the assignment.


o is not required to be dereferenceable after evaluating any of the assignment
expressions above. If e is an xvalue, the resulting state of the object it denotes
is valid but unspecified.


Equality preservation


Expressions declared in requires expressions of the standard library concepts are
required to be equality-preserving (except where stated otherwise).

Notes


The only valid use of operator* is on the left side of an assignment expression.
Assignment through the same value of an indirectly writable type may happen only
once.


The required expressions with const_cast prevent indirectly_readable objects with
prvalue reference types from satisfying the syntactic requirements of
indirectly_writable by accident, while permitting proxy references to continue to
work as long as their constness is shallow. See Ranges TS issue 381.

2024.06.10 http://cppreference.com