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std::experimental::ranges::CommonReference(3) C++ Standard Libary std::experimental::ranges::CommonReference(3)


std::experimental::ranges::CommonReference - std::experimental::ranges::CommonReference


Defined in header <experimental/ranges/concepts>
template < class T, class U >

concept bool CommonReference =
Same<ranges::common_reference_t<T, U>, ranges::common_reference_t<U, (ranges TS)
T>> &&
ConvertibleTo<T, ranges::common_reference_t<T, U>> &&

ConvertibleTo<U, ranges::common_reference_t<T, U>>;

The concept CommonReference<T, U> specifies that two types T and U share a common
reference type (as computed by ranges::common_reference_t) to which both can be

CommonReference<T, U> is satisfied only if, given expressions t and u such that
decltype((t)) is T and decltype((u)) is U,

* ranges::common_reference_t<T, U>(t) is equal to ranges::common_reference_t<T,
U>(t) if and only if t is an equality-preserving expression; and
* ranges::common_reference_t<T, U>(u) is equal to ranges::common_reference_t<T,
U>(u) if and only if u is an equality-preserving expression.

In other words, the conversion to the common reference type must not alter the
equality-preservation property of the original expression.

Equality preservation

An expression is equality preserving if it results in equal outputs given equal

* The inputs to an expression consist of its operands.
* The outputs of an expression consist of its result and all operands modified by
the expression (if any).

Every expression required to be equality preserving is further required to be
stable: two evaluations of such an expression with the same input objects must have
equal outputs absent any explicit intervening modification of those input objects.

See also

common_reference determine the common reference type of a set of types
(class template)
Common specifies that two types share a common type
common_type determine the common type of a set of types
(class template)