table of contents
std::expected::transform(3) | C++ Standard Libary | std::expected::transform(3) |
NAME¶
std::expected::transform - std::expected::transform
Synopsis¶
template< class F > (1) (since C++23)
constexpr auto transform( F&& f ) &;
template< class F > (2) (since C++23)
constexpr auto transform( F&& f ) const&;
template< class F > (3) (since C++23)
constexpr auto transform( F&& f ) &&;
template< class F > (4) (since C++23)
constexpr auto transform( F&& f ) const&&;
If *this contains an expected value, invokes f and returns a std::expected
object
that contains its result; otherwise, returns a std::expected object that
contains a
copy of error().
If T is not (possibly cv-qualified) void, the contained value (obtained from
operator*) is passed as an argument to f; otherwise f takes no argument.
1,2) Given type U as
* std::remove_cv_t<std::invoke_result_t<F>> if T is (possibly
cv-qualified) void,
or
* std::remove_cv_t<std::invoke_result_t<F, decltype(**this)>>
otherwise,
and expression /* invoke-expr */ as
* std::invoke(std::forward<F>(f)) if T is (possibly cv-qualified) void,
or
* std::invoke(std::forward<F>(f), **this) otherwise.
If U is not a valid value type for std::expected, or U u(/* invoke-expr */);
is
ill-formed when std::is_void_v<U> is false, the program is ill-formed.
The effect is equivalent to
if (has_value())
{
if constexpr (std::is_void_v<U>)
{
/* invoke-expr */;
return std::expected<U, E>();
}
else
// the returned std::expected object contains an expected value,
// which is direct-non-list-initialized with /* invoke-expr */
return /* an std::expected<U, E> object */;
}
else
return std::expected<U, E>(std::unexpect, error());
These overloads participate in overload resolution only if
std::is_constructible_v<E, decltype(error())> is true.
3,4) Given type U as
* std::remove_cv_t<std::invoke_result_t<F>> if T is (possibly
cv-qualified) void,
or
* std::remove_cv_t<std::invoke_result_t<F,
decltype(std::move(**this))>>
otherwise,
and expression /* invoke-expr */ as
* std::invoke(std::forward<F>(f)) if T is (possibly cv-qualified) void,
or
* std::invoke(std::forward<F>(f), std::move(**this)) otherwise.
If U is not a valid value type for std::expected, or U u(/* invoke-expr */);
is
ill-formed when std::is_void_v<U> is false, the program is ill-formed.
The effect is equivalent to
if (has_value())
{
if constexpr (std::is_void_v<U>)
{
/* invoke-expr */;
return std::expected<U, E>();
}
else
// the returned std::expected object contains an expected value,
// which is direct-non-list-initialized with /* invoke-expr */
return /* an std::expected<U, E> object */;
}
else
return std::expected<U, E>(std::unexpect, std::move(error()));
These overloads participate in overload resolution only if
std::is_constructible_v<E, decltype(std::move(error()))> is true.
Parameters¶
f - a suitable function or Callable object whose call signature
returns a
non-reference type
Return value¶
A std::expected object containing either the result of f or an
error value, as
described above.
Example¶
This section is incomplete
Reason: no example
Defect reports
The following behavior-changing defect reports were applied retroactively to
previously published C++ standards.
DR Applied to Behavior as published Correct behavior
LWG 3938 C++23 transform was ill-formed if T is not (possibly made
well-formed
cv-qualified) void and E is not copyable
See also¶
returns the expected itself if it contains an expected value;
transform_error otherwise, returns an expected containing the transformed
unexpected
value
(public member function)
Category:¶
* Todo no example
2024.06.10 | http://cppreference.com |