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std::disjunction(3) C++ Standard Libary std::disjunction(3)

NAME

std::disjunction - std::disjunction

Synopsis


Defined in header <type_traits>
template< class... B > (since C++17)
struct disjunction;


Forms the logical disjunction of the type traits B..., effectively performing a
logical OR on the sequence of traits.


The specialization std::disjunction<B1, ..., BN> has a public and unambiguous base
that is


* if sizeof...(B) == 0, std::false_type; otherwise
* the first type Bi in B1, ..., BN for which bool(Bi::value) == true, or BN if
there is no such type.


The member names of the base class, other than disjunction and operator=, are not
hidden and are unambiguously available in disjunction.


Disjunction is short-circuiting: if there is a template type argument Bi with
bool(Bi::value) != false, then instantiating disjunction<B1, ..., BN>::value does
not require the instantiation of Bj::value for j > i.


If the program adds specializations for std::disjunction or std::disjunction_v, the
behavior is undefined.

Template parameters


B... - every template argument Bi for which Bi::value is instantiated must be usable
as a base class and define member value that is convertible to bool


Helper variable template


template< class... B > (since C++17)
inline constexpr bool disjunction_v = disjunction<B...>::value;

Possible implementation


template<class...> struct disjunction : std::false_type {};
template<class B1> struct disjunction<B1> : B1 {};
template<class B1, class... Bn>
struct disjunction<B1, Bn...>
: std::conditional_t<bool(B1::value), B1, disjunction<Bn...>> {};

Notes


A specialization of disjunction does not necessarily inherit from of either
std::true_type or std::false_type: it simply inherits from the first B whose
::value, explicitly converted to bool, is true, or from the very last B when all of
them convert to false. For example, std::disjunction<std::integral_constant<int, 2>,
std::integral_constant<int, 4>>::value is 2.


The short-circuit instantiation differentiates disjunction from fold expressions: a
fold expression like (... || Bs::value) instantiates every B in Bs, while
std::disjunction_v<Bs...> stops instantiation once the value can be determined. This
is particularly useful if the later type is expensive to instantiate or can cause a
hard error when instantiated with the wrong type.


Feature-test macro Value Std Feature
__cpp_lib_logical_traits 201510L (C++17) Logical operator type traits

Example

// Run this code


#include <cstdint>
#include <string>
#include <type_traits>


// values_equal<a, b, T>::value is true if and only if a == b.
template<auto V1, decltype(V1) V2, typename T>
struct values_equal : std::bool_constant<V1 == V2>
{
using type = T;
};


// default_type<T>::value is always true
template<typename T>
struct default_type : std::true_type
{
using type = T;
};


// Now we can use disjunction like a switch statement:
template<int I>
using int_of_size = typename std::disjunction< //
values_equal<I, 1, std::int8_t>, //
values_equal<I, 2, std::int16_t>, //
values_equal<I, 4, std::int32_t>, //
values_equal<I, 8, std::int64_t>, //
default_type<void> // must be last!
>::type;


static_assert(sizeof(int_of_size<1>) == 1);
static_assert(sizeof(int_of_size<2>) == 2);
static_assert(sizeof(int_of_size<4>) == 4);
static_assert(sizeof(int_of_size<8>) == 8);
static_assert(std::is_same_v<int_of_size<13>, void>);


// checking if Foo is constructible from double will cause a hard error
struct Foo
{
template<class T>
struct sfinae_unfriendly_check { static_assert(!std::is_same_v<T, double>); };


template<class T>
Foo(T, sfinae_unfriendly_check<T> = {});
};


template<class... Ts>
struct first_constructible
{
template<class T, class...Args>
struct is_constructible_x : std::is_constructible<T, Args...>
{
using type = T;
};
struct fallback
{
static constexpr bool value = true;
using type = void; // type to return if nothing is found
};


template<class... Args>
using with = typename std::disjunction<is_constructible_x<Ts, Args...>...,
fallback>::type;
};


// OK, is_constructible<Foo, double> not instantiated
static_assert(std::is_same_v<first_constructible<std::string, int, Foo>::with<double>,
int>);


static_assert(std::is_same_v<first_constructible<std::string, int>::with<>, std::string>);
static_assert(std::is_same_v<first_constructible<std::string, int>::with<const char*>,
std::string>);
static_assert(std::is_same_v<first_constructible<std::string, int>::with<void*>, void>);


int main() {}

See also


negation logical NOT metafunction
(C++17) (class template)
conjunction variadic logical AND metafunction
(C++17) (class template)

2024.06.10 http://cppreference.com