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| std::destroy(3) | C++ Standard Libary | std::destroy(3) | 
NAME¶
std::destroy - std::destroy
Synopsis¶
 Defined in header <memory>
  
   template< class ForwardIt > (since C++17)
  
   void destroy( ForwardIt first, ForwardIt last ); (until C++20)
  
   template< class ForwardIt > (since C++20)
  
   constexpr void destroy( ForwardIt first, ForwardIt last ); (1)
  
   template< class ExecutionPolicy, class ForwardIt >
  
   void destroy( ExecutionPolicy&& policy, ForwardIt first, (2)
    (since C++17)
  
   ForwardIt last );
  
   1) Destroys the objects in the range [first, last), as if by
  
   for (; first != last; ++first)
  
   std::destroy_at(std::addressof(*first));
  
   2) Same as (1), but executed according to policy. This overload
    participates in
  
   overload resolution only if
  
   std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is
    true. (until
  
   C++20)
  
   std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>>
    is true. (since
  
   C++20)
Parameters¶
 first, last - the range of elements to destroy
  
   policy - the execution policy to use. See execution policy for
  
   details.
Type requirements¶
 -
  
   ForwardIt must meet the requirements of LegacyForwardIterator.
  
   -
  
   No increment, assignment, comparison, or indirection through valid instances
    of
  
   ForwardIt may throw exceptions.
Return value¶
(none)
Complexity¶
Linear in the distance between first and last.
Exceptions¶
 The overload with a template parameter named ExecutionPolicy
    reports errors as
  
   follows:
  
   * If execution of a function invoked as part of the algorithm throws an
    exception
  
   and ExecutionPolicy is one of the standard policies, std::terminate is
    called.
  
   For any other ExecutionPolicy, the behavior is implementation-defined.
  
   * If the algorithm fails to allocate memory, std::bad_alloc is thrown.
Possible implementation¶
 template<class ForwardIt>
  
   constexpr // since C++20
  
   void destroy(ForwardIt first, ForwardIt last)
  
   {
  
   for (; first != last; ++first)
  
   std::destroy_at(std::addressof(*first));
  
   }
Example¶
 The following example demonstrates how to use destroy to destroy
    a contiguous
  
   sequence of elements.
// Run this code
  
   #include <iostream>
  
   #include <memory>
  
   #include <new>
  
   struct Tracer
  
   {
  
   int value;
  
   ~Tracer() { std::cout << value << " destructed\n"; }
  
   };
  
   int main()
  
   {
  
   alignas(Tracer) unsigned char buffer[sizeof(Tracer) * 8];
  
   for (int i = 0; i < 8; ++i)
  
   new(buffer + sizeof(Tracer) * i) Tracer{i}; //manually construct objects
  
   auto ptr = std::launder(reinterpret_cast<Tracer*>(buffer));
  
   std::destroy(ptr, ptr + 8);
  
   }
Output:¶
 0 destructed
  
   1 destructed
  
   2 destructed
  
   3 destructed
  
   4 destructed
  
   5 destructed
  
   6 destructed
  
   7 destructed
See also¶
 destroy_n destroys a number of objects in a range
  
   (C++17) (function template)
  
   destroy_at destroys an object at a given address
  
   (C++17) (function template)
  
   ranges::destroy destroys a range of objects
  
   (C++20) (niebloid)
| 2024.06.10 | http://cppreference.com |