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std::declval(3) | C++ Standard Libary | std::declval(3) |
NAME¶
std::declval - std::declval
Synopsis¶
Defined in header <utility>
template< class T > (since C++11)
typename std::add_rvalue_reference<T>::type declval() noexcept;
Converts any type T to a reference type, making it possible to use member
functions
in the operand of the decltype specifier without the need to go through
constructors.
std::declval is commonly used in templates where acceptable template
parameters may
have no constructor in common, but have the same member function whose return
type
is needed.
Note that std::declval can only be used in unevaluated contexts and is not
required
to be defined; it is an error to evaluate an expression that contains this
function.
Formally, the program is ill-formed if this function is odr-used.
Parameters¶
(none)
Return value¶
Cannot be called and thus never returns a value. The return type
is T&& unless T is
(possibly cv-qualified) void, in which case the return type is T.
Possible implementation¶
template<typename T>
typename std::add_rvalue_reference<T>::type declval() noexcept
{
static_assert(false, "declval not allowed in an evaluated
context");
}
Example¶
// Run this code
#include <iostream>
#include <utility>
struct Default
{
int foo() const { return 1; }
};
struct NonDefault
{
NonDefault() = delete;
int foo() const { return 1; }
};
int main()
{
decltype(Default().foo()) n1 = 1; // type of n1 is int
// decltype(NonDefault().foo()) n2 = n1; // error: no default constructor
decltype(std::declval<NonDefault>().foo()) n2 = n1; // type of n2 is
int
std::cout << "n1 = " << n1 << '\n'
<< "n2 = " << n2 << '\n';
}
Output:¶
n1 = 1
n2 = 1
See also¶
decltype specifier(C++11) obtains the type of an
expression or an entity
result_of deduces the result type of invoking a callable object with
invoke_result a set of arguments
(C++11)(removed in C++20) (class template)
(C++17)
2024.06.10 | http://cppreference.com |