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std::compare_strong_order_fallback(3) C++ Standard Libary std::compare_strong_order_fallback(3)

NAME

std::compare_strong_order_fallback - std::compare_strong_order_fallback

Synopsis


Defined in header <compare>
inline namespace /* unspecified */ {


inline constexpr /* unspecified */ (since C++20)
compare_strong_order_fallback = /* unspecified */;


}
Call signature
template< class T, class U >


requires /* see below */
constexpr std::strong_ordering


compare_strong_order_fallback(T&& t, U&& u) noexcept(/* see below
*/);


Performs three-way comparison on t and u and produces a result of type
std::strong_ordering, even if the operator <=> is unavailable.


Let t and u be expressions and T and U denote decltype((t)) and decltype((u))
respectively, std::compare_strong_order_fallback(t, u) is expression-equivalent to:


* If std::is_same_v<std::decay_t<T>, std::decay_t<U>> is true:


* std::strong_order(t, u), if it is a well-formed expression;
* otherwise,


t == u ? std::strong_ordering::equal :
t < u ? std::strong_ordering::less :
std::strong_ordering::greater


if t == u and t < u are both well-formed and convertible to
bool, except that t and u are evaluated only once.


* In all other cases, std::compare_strong_order_fallback(t, u) is ill-formed,
which can result in substitution failure when it appears in the immediate
context of a template instantiation.


Expression-equivalent


Expression e is expression-equivalent to expression f, if


* e and f have the same effects, and
* either both are constant subexpressions or else neither is a constant
subexpression, and
* either both are potentially-throwing or else neither is potentially-throwing
(i.e. noexcept(e) == noexcept(f)).


Customization point objects


The name std::compare_strong_order_fallback denotes a customization point object,
which is a const function object of a literal semiregular class type. For exposition
purposes, the cv-unqualified version of its type is denoted as
__compare_strong_order_fallback_fn.


All instances of __compare_strong_order_fallback_fn are equal. The effects of
invoking different instances of type __compare_strong_order_fallback_fn on the same
arguments are equivalent, regardless of whether the expression denoting the instance
is an lvalue or rvalue, and is const-qualified or not (however, a volatile-qualified
instance is not required to be invocable). Thus, std::compare_strong_order_fallback
can be copied freely and its copies can be used interchangeably.


Given a set of types Args..., if std::declval<Args>()... meet the requirements for
arguments to std::compare_strong_order_fallback above,
__compare_strong_order_fallback_fn models


* std::invocable<__compare_strong_order_fallback_fn, Args...>,
* std::invocable<const __compare_strong_order_fallback_fn, Args...>,
* std::invocable<__compare_strong_order_fallback_fn&, Args...>, and
* std::invocable<const __compare_strong_order_fallback_fn&, Args...>.


Otherwise, no function call operator of __compare_strong_order_fallback_fn
participates in overload resolution.

Example


This section is incomplete
Reason: no example

See also


strong_order performs 3-way comparison and produces a result of type
(C++20) std::strong_ordering
(customization point object)

2022.07.31 http://cppreference.com