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| std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,(3) | C++ Standard Libary | std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,(3) | 
NAME¶
std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month, - std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,
Synopsis¶
std::chrono::year_month_weekday_last::weekday_last
  
   constexpr std::chrono::year year() const noexcept; (1) (since
    C++20)
  
   constexpr std::chrono::month month() const noexcept; (2) (since
    C++20)
  
   constexpr std::chrono::weekday weekday() const noexcept; (3) (since
    C++20)
  
   constexpr std::chrono::weekday_last weekday_last() const noexcept; (4)
    (since C++20)
  
   Retrieves the field values stored in this year_month_weekday_last object.
Return value¶
 1) Returns the stored std::chrono::year value.
  
   2) Returns the stored std::chrono::month value.
  
   3) Returns the stored std::chrono::weekday value.
  
   4) std::chrono::weekday_last(weekday())
Example¶
// Run this code
  
   #include <chrono>
  
   #include <iostream>
  
   using namespace std::chrono;
  
   int main()
  
   {
  
   auto ymwdl{Tuesday[last]/November/2022};
  
   auto wdl = ymwdl.weekday_last();
  
   wdl = (wdl.weekday() + days(1))[last];
  
   ymwdl = {ymwdl.year() + years(1), ymwdl.month() - months(2), wdl};
  
   std::cout << year_month_day(ymwdl) << '\n';
  
   }
Output:¶
2023-09-27
| 2024.06.10 | http://cppreference.com |