table of contents
std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,(3) | C++ Standard Libary | std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,(3) |
NAME¶
std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month, - std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,
Synopsis¶
std::chrono::year_month_weekday_last::weekday_last
constexpr std::chrono::year year() const noexcept; (1) (since
C++20)
constexpr std::chrono::month month() const noexcept; (2) (since
C++20)
constexpr std::chrono::weekday weekday() const noexcept; (3) (since
C++20)
constexpr std::chrono::weekday_last weekday_last() const noexcept; (4)
(since C++20)
Retrieves the field values stored in this year_month_weekday_last object.
Return value¶
1) Returns the stored std::chrono::year value.
2) Returns the stored std::chrono::month value.
3) Returns the stored std::chrono::weekday value.
4) std::chrono::weekday_last(weekday())
Example¶
// Run this code
#include <chrono>
#include <iostream>
using namespace std::chrono;
int main()
{
auto ymwdl{Tuesday[last]/November/2022};
auto wdl = ymwdl.weekday_last();
wdl = (wdl.weekday() + days(1))[last];
ymwdl = {ymwdl.year() + years(1), ymwdl.month() - months(2), wdl};
std::cout << year_month_day(ymwdl) << '\n';
}
Output:¶
2023-09-27
2024.06.10 | http://cppreference.com |