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std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,(3) C++ Standard Libary std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,(3)

NAME

std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month, - std::chrono::year_month_weekday_last::year,std::chrono::year_month_weekday_last::month,

Synopsis


std::chrono::year_month_weekday_last::weekday_last


constexpr std::chrono::year year() const noexcept; (1) (since C++20)
constexpr std::chrono::month month() const noexcept; (2) (since C++20)
constexpr std::chrono::weekday weekday() const noexcept; (3) (since C++20)
constexpr std::chrono::weekday_last weekday_last() const noexcept; (4) (since C++20)


Retrieves the field values stored in this year_month_weekday_last object.

Return values


1) Returns the stored std::chrono::year value.
2) Returns the stored std::chrono::month value.
3) Returns the stored std::chrono::weekday value.
4) std::chrono::weekday_last(weekday()).

Example

// Run this code


#include <iostream>
#include <chrono>
using namespace std::chrono;


int main()
{
std::cout << std::boolalpha;


auto ymwdl {Tuesday[last]/November/2022};
auto wdl = ymwdl.weekday_last();
wdl = (wdl.weekday() + days(1))[last];
ymwdl = {ymwdl.year() + years(1), ymwdl.month() - months(2), wdl};
std::cout << (year_month_day(ymwdl) == September/27/2023) << '\n';
}

Output:


true

2022.07.31 http://cppreference.com