NAME¶

std::chrono::year_month_weekday_last::operatorsys_days, - std::chrono::year_month_weekday_last::operatorsys_days,

Synopsis¶

constexpr operator std::chrono::sys_days() const noexcept; (1) (since C++20)
explicit constexpr operator std::chrono::local_days() const (2) (since C++20)
noexcept;

Converts *this to a std::chrono::time_point representing the same date as this
year_month_weekday_last.

1) If ok() is true, returns a sys_days that represents the last weekday() of the
year() and month(). Otherwise, the returned value is unspecified.
2) Same as (1), but returns local_days instead of sys_days. Equivalent to
local_days(sys_days(*this).time_since_epoch()).

Example¶

// Run this code

#include <iostream>
#include <chrono>
using namespace std::chrono;

int main()
{
std::cout << std::boolalpha;

constexpr auto ymwdl {Tuesday[last]/11/2021};
static_assert(static_cast<local_days>(ymwdl) ==
static_cast<local_days>(November/30/2021));
// convert from field-based to serial-based to add days
constexpr auto sd = static_cast<sys_days>(ymwdl);
constexpr year_month_day ymd {sd + days(10)};
std::cout << (ymd == December/10/2021) << '\n';
}

Output:¶

true