NAME¶

std::chrono::operator==,(std::chrono::year_month_day_last) - std::chrono::operator==,(std::chrono::year_month_day_last)

Synopsis¶

Defined in header <chrono>
constexpr bool operator==( const std::chrono::year_month_day_last&
x, (1) (since C++20)
const std::chrono::year_month_day_last& y ) noexcept;
constexpr std::strong_ordering

operator<=>( const std::chrono::year_month_day_last& x, (2) (since C++20)

const std::chrono::year_month_day_last& y ) noexcept;

Compares the two year_month_day_last values x and y. This is a lexicographical
comparison: the year() is compared first, then month().

The <, <=, >, >=, and != operators are synthesized from operator<=> and operator==
respectively.

Return value¶

1) x.year() == y.year() && x.month() == y.month()
2) x.year() <=> y.year() != 0 ? x.year() <=> y.year() : x.month() <=> y.month()

Notes¶

If both x and y represent valid dates (x.ok() && y.ok() == true), the result of the
lexicographical comparison is consistent with the calendar order.

Example¶

// Run this code

#include <iostream>
#include <chrono>

int main()
{
std::cout << std::boolalpha;

auto ymdl1 {11/std::chrono::last/2020};
auto mdl {std::chrono::last/std::chrono::November};
auto ymdl2 {mdl/2020};
std::cout << (ymdl1 == ymdl2) << ' ';
ymdl1 -= std::chrono::months{2};
ymdl2 -= std::chrono::months{1};
std::cout << (ymdl1 < ymdl2) << '\n';
}

Output:¶

true true