NAME¶

std::chrono::operator==,(std::chrono::year_month_day) - std::chrono::operator==,(std::chrono::year_month_day)

Synopsis¶

Defined in header <chrono>
constexpr bool operator==( const std::chrono::year_month_day& x, (1) (since C++20)
const std::chrono::year_month_day& y ) noexcept;
constexpr std::strong_ordering

operator<=>( const std::chrono::year_month_day& x, (2) (since C++20)

const std::chrono::year_month_day& y ) noexcept;

Compares the two year_month_day values x and y. This is a lexicographical
comparison: the year() is compared first, then month(), then day().

The <, <=, >, >=, and != operators are synthesized from operator<=> and operator==
respectively.

Return value¶

1) x.year() == y.year() && x.month() == y.month() && x.day() == y.day()
2) If x.year() <=> y.year != 0, x.year() <=> y.year; otherwise if x.month() <=>
y.month() != 0, x.month() <=> y.month(); otherwise x.day() <=> y.day()

Notes¶

If both x and y represent valid dates (x.ok() && y.ok() == true), the result of the
lexicographical comparison is consistent with the calendar order.

Example¶

// Run this code

#include <iostream>
#include <chrono>

int main()
{
constexpr auto ymd1 {std::chrono::day(1)/7/2021};
constexpr auto ymd2 {std::chrono::year(2021)/7/1};
std::cout << std::boolalpha << (ymd1 == ymd2) << '\n';

static_assert(ymd1 <= ymd2);
}

Output:¶

true