table of contents
std::chrono::hh_mm_ss::is_negative,std::chrono::hh_mm_ss::hours,(3) | C++ Standard Libary | std::chrono::hh_mm_ss::is_negative,std::chrono::hh_mm_ss::hours,(3) |
NAME¶
std::chrono::hh_mm_ss::is_negative,std::chrono::hh_mm_ss::hours, - std::chrono::hh_mm_ss::is_negative,std::chrono::hh_mm_ss::hours,
Synopsis¶
std::chrono::hh_mm_ss<Duration>::subseconds
constexpr bool is_negative() const noexcept; (1)
constexpr std::chrono::hours hours() const noexcept; (2)
constexpr std::chrono::minutes minutes() const noexcept; (3)
constexpr std::chrono::seconds seconds() const noexcept; (4)
constexpr precision subseconds() const noexcept; (5)
Obtains the components of the stored "broken down" time.
Return value¶
Let d be the represented duration:
1) true if d is negative, false otherwise.
2) std::chrono::duration_cast<std::chrono::hours>(abs(d))
3) std::chrono::duration_cast<std::chrono::minutes>(abs(d) - hours())
4) std::chrono::duration_cast<std::chrono::seconds>(abs(d) - hours() -
minutes())
5) abs(d) - hours() - minutes() - seconds() if
std::chrono::treat_as_floating_point_v<precision::rep> is true;
otherwise
std::chrono::duration_cast<precision>(abs(d) - hours() - minutes() -
seconds()).
Example¶
This section is incomplete
Reason: no example
Category:¶
* Todo no example
2024.06.10 | http://cppreference.com |