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| std::align(3) | C++ Standard Libary | std::align(3) | 
NAME¶
std::align - std::align
Synopsis¶
 Defined in header <memory>
  
   void* align( std::size_t alignment,
  
   std::size_t size, (since C++11)
  
   void*& ptr,
  
   std::size_t& space );
  
   Given a pointer ptr to a buffer of size space, returns a pointer aligned by
    the
  
   specified alignment for size number of bytes and decreases space argument by
    the
  
   number of bytes used for alignment. The first aligned address is
  returned.
  
   The function modifies the pointer only if it would be possible to fit the
    wanted
  
   number of bytes aligned by the given alignment into the buffer. If the buffer
    is too
  
   small, the function does nothing and returns nullptr.
  
   The behavior is undefined if alignment is not a power of two.
Parameters¶
 alignment - the desired alignment
  
   size - the size of the storage to be aligned
  
   ptr - pointer to contiguous storage (a buffer) of at least space bytes
  
   space - the size of the buffer in which to operate
Return value¶
The adjusted value of ptr, or null pointer value if the space provided is too small.
Example¶
Demonstrates the use of std::align to place objects of different type in memory.
// Run this code
  
   #include <iostream>
  
   #include <memory>
  
   template<std::size_t N>
  
   struct MyAllocator
  
   {
  
   char data[N];
  
   void* p;
  
   std::size_t sz;
  
   MyAllocator() : p(data), sz(N) {}
  
   template<typename T>
  
   T* aligned_alloc(std::size_t a = alignof(T))
  
   {
  
   if (std::align(a, sizeof(T), p, sz))
  
   {
  
   T* result = reinterpret_cast<T*>(p);
  
   p = (char*)p + sizeof(T);
  
   sz -= sizeof(T);
  
   return result;
  
   }
  
   return nullptr;
  
   }
  
   };
  
   int main()
  
   {
  
   MyAllocator<64> a;
  
   std::cout << "allocated a.data at " << (void*)a.data
  
   << " (" << sizeof a.data << "
    bytes)\n";
  
   // allocate a char
  
   if (char* p = a.aligned_alloc<char>())
  
   {
  
   *p = 'a';
  
   std::cout << "allocated a char at " << (void*)p
    << '\n';
  
   }
  
   // allocate an int
  
   if (int* p = a.aligned_alloc<int>())
  
   {
  
   *p = 1;
  
   std::cout << "allocated an int at " << (void*)p
    << '\n';
  
   }
  
   // allocate an int, aligned at 32-byte boundary
  
   if (int* p = a.aligned_alloc<int>(32))
  
   {
  
   *p = 2;
  
   std::cout << "allocated an int at " << (void*)p
    << " (32 byte alignment)\n";
  
   }
  
   }
Possible output:¶
 allocated a.data at 0x7ffd0b331f80 (64 bytes)
  
   allocated a char at 0x7ffd0b331f80
  
   allocated an int at 0x7ffd0b331f84
  
   allocated an int at 0x7ffd0b331fa0 (32 byte alignment)
  
   Defect reports
  
   The following behavior-changing defect reports were applied retroactively to
  
   previously published C++ standards.
  
   DR Applied to Behavior as published Correct behavior
  
   LWG 2377 C++11 alignment required to be a fundamental only need to be a power
  
   or supported extended alignment value of two
See also¶
 alignof operator(C++11) queries alignment requirements of
    a type
  
   alignas specifier(C++11) specifies that the storage for the variable
    should be
  
   aligned by specific amount
  
   aligned_storage defines the type suitable for use as uninitialized
  
   (C++11)(deprecated in C++23) storage for types of given size
  
   (class template)
  
   assume_aligned informs the compiler that a pointer is aligned
  
   (C++20) (function template)
| 2024.06.10 | http://cppreference.com |