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    | std::chrono::utc_clock::now(3) | C++ Standard Libary | std::chrono::utc_clock::now(3) | 
NAME¶
std::chrono::utc_clock::now - std::chrono::utc_clock::now
Synopsis¶
static std::chrono::time_point<std::chrono::utc_clock> now(); (since C++20)
  
   Returns a time point representing the current point in time. The result is
  
   calculated as if by
  
   std::chrono::utc_clock::from_sys(std::chrono::system_clock::now()).
    Implementations
  
   may use a more accurate value of UTC time.
Parameters¶
(none)
Return value¶
A time point representing the current time.
Example¶
// Run this code
  
   #include <iostream>
  
   #include <iomanip>
  
   #include <vector>
  
   #include <numeric>
  
   #include <chrono>
  
   volatile int sink;
  
   int main()
  
   {
  
   std::cout << std::fixed << std::setprecision(9) <<
    std::left;
  
   for (auto size = 1ull; size < 1000'000'000ull; size *= 100) {
  
   // record start time
  
   auto start = std::chrono::utc_clock::now();
  
   // do some work
  
   std::vector<int> v(size, 42);
  
   sink = std::accumulate(v.begin(), v.end(), 0u); // make sure it's a side
    effect
  
   // record end time
  
   auto end = std::chrono::utc_clock::now();
  
   std::chrono::duration<double> diff = end - start;
  
   std::cout << "Time to fill and iterate a vector of " <<
    std::setw(9)
  
   << size << " ints : " << diff.count() <<
    " s\n";
  
   }
  
   }
Possible output:¶
 Time to fill and iterate a vector of 1 ints : 0.000006568 s
  
   Time to fill and iterate a vector of 100 ints : 0.000002854 s
  
   Time to fill and iterate a vector of 10000 ints : 0.000116290 s
  
   Time to fill and iterate a vector of 1000000 ints : 0.011742752 s
  
   Time to fill and iterate a vector of 100000000 ints : 0.505534949 s
| 2022.07.31 | http://cppreference.com |