table of contents
std::strtok(3) | C++ Standard Libary | std::strtok(3) |
NAME¶
std::strtok - std::strtok
Synopsis¶
Defined in header <cstring>
char* strtok( char* str, const char* delim );
Finds the next token in a null-terminated byte string pointed to by str. The
separator characters are identified by null-terminated byte string pointed to
by
delim.
This function is designed to be called multiple times to obtain successive
tokens
from the same string.
* If str is not a null pointer, the call is treated as the first call to
strtok
for this particular string. The function searches for the first character
which
is not contained in delim.
* If no such character was found, there are no tokens in str at all, and
the function returns a null pointer.
* If such character was found, it is the beginning of the token. The
function then searches from that point on for the first character that
is contained in delim.
* If no such character was found, str has only one token,
and the future calls to strtok will return a null pointer
* If such character was found, it is replaced by the null
character '\0' and the pointer to the following character
is stored in a static location for subsequent invocations.
* The function then returns the pointer to the beginning of the token
* If str is a null pointer, the call is treated as a subsequent call to
strtok:
the function continues from where it left in previous invocation. The
behavior
is the same as if the previously stored pointer is passed as str.
Parameters¶
str - pointer to the null-terminated byte string to tokenize
delim - pointer to the null-terminated byte string identifying delimiters
Return value¶
Pointer to the beginning of the next token or a nullptr if there are no more tokens.
Notes¶
This function is destructive: it writes the '\0' characters in
the elements of the
string str. In particular, a string literal cannot be used as the first
argument of
std::strtok.
Each call to this function modifies a static variable: is not thread
safe.
Unlike most other tokenizers, the delimiters in std::strtok can be different
for
each subsequent token, and can even depend on the contents of the previous
tokens.
Example¶
// Run this code
#include <cstring>
#include <iostream>
#include <iomanip>
int main()
{
char input[] = "one + two * (three - four)!";
const char* delimiters = "! +- (*)";
char *token = std::strtok(input, delimiters);
while (token) {
std::cout << std::quoted(token) << ' ';
token = std::strtok(nullptr, delimiters);
}
std::cout << "\nContents of the input string now:\n\"";
for (std::size_t n = 0; n < sizeof input; ++n) {
if (const char c = input[n]; c != '\0')
std::cout << c;
else
std::cout << "\\0";
}
std::cout << "\"\n";
}
Output:¶
"one" "two" "three"
"four"
Contents of the input string now:
"one\0+ two\0* (three\0- four\0!\0"
See also¶
finds the first location of any character from a set of
strpbrk separators
(function)
returns the length of the maximum initial segment that consists
strcspn of only the characters not found in another byte string
(function)
returns the length of the maximum initial segment that consists
strspn of only the characters found in another byte string
(function)
ranges::split_view a view over the subranges obtained from splitting another
view
views::split using a delimiter
(C++20) (class template) (range adaptor object)
2022.07.31 | http://cppreference.com |