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std::ranges::prev(3) C++ Standard Libary std::ranges::prev(3)

NAME

std::ranges::prev - std::ranges::prev

Synopsis


Defined in header <iterator>
Call signature
template< std::bidirectional_iterator I > (1) (since C++20)
constexpr I prev( I i );
template< std::bidirectional_iterator I > (2) (since C++20)
constexpr I prev( I i, std::iter_difference_t<I> n );
template< std::bidirectional_iterator I > (3) (since C++20)
constexpr I prev( I i, std::iter_difference_t<I> n, I bound );


Return the n^th predecessor of iterator i.


The function-like entities described on this page are niebloids, that is:


* Explicit template argument lists cannot be specified when calling any of them.
* None of them are visible to argument-dependent lookup.
* When any of them are found by normal unqualified lookup as the name to the left
of the function-call operator, argument-dependent lookup is inhibited.


In practice, they may be implemented as function objects, or with special compiler
extensions.

Parameters


i - an iterator
n - number of elements i should be descended
bound - iterator denoting the beginning of the range i points to

Return value


1) The predecessor of i.
2) The n^th predecessor of iterator i.
3) The n^th predecessor of iterator i, or the first iterator that compares equal to
bound, whichever is first.

Complexity


1) Constant.
2,3) Constant if I models std::random_access_iterator<I>; otherwise linear.

Possible implementation


struct prev_fn
{
template<std::bidirectional_iterator I>
constexpr I operator()(I i) const
{
--i;
return i;
}


template<std::bidirectional_iterator I>
constexpr I operator()(I i, std::iter_difference_t<I> n) const
{
ranges::advance(i, -n);
return i;
}


template<std::bidirectional_iterator I>
constexpr I operator()(I i, std::iter_difference_t<I> n, I bound) const
{
ranges::advance(i, -n, bound);
return i;
}
};


inline constexpr auto prev = prev_fn();

Notes


Although the expression --r.end() often compiles for containers, it is not
guaranteed to do so: r.end() is an rvalue expression, and there is no iterator
requirement that specifies that decrement of an rvalue is guaranteed to work. In
particular, when iterators are implemented as pointers or its operator-- is
lvalue-ref-qualified, --r.end() does not compile, while ranges::prev(r.end()) does.


This is further exacerbated by ranges that do not model ranges::common_range. For
example, for some underlying ranges, ranges::transform_view::end doesn't have the
same return type as ranges::transform_view::begin, and so --r.end() won't compile.
This isn't something that ranges::prev can aid with, but there are workarounds.

Example

// Run this code


#include <iostream>
#include <iterator>
#include <vector>


int main()
{
std::vector<int> v{3, 1, 4};
auto pv = std::ranges::prev(v.end(), 2);
std::cout << *pv << '\n';


pv = std::ranges::prev(pv, 42, v.begin());
std::cout << *pv << '\n';
}

Output:


1
3

See also


ranges::next increment an iterator by a given distance or to a bound
(C++20) (niebloid)
ranges::advance advances an iterator by given distance or to a given bound
(C++20) (niebloid)
prev decrement an iterator
(C++11) (function template)

2024.06.10 http://cppreference.com