NAME¶

std::literals::chrono_literals::operator""y - std::literals::chrono_literals::operator""y

Synopsis¶

Defined in header <chrono>
constexpr std::chrono::year operator ""y( unsigned long long y ) (1) (since C++20)
noexcept;

Forms a std::chrono::year literal representing a year in the proleptic Gregorian
calendar.

Parameters¶

y - the year value

Return value¶

A std::chrono::year initialized from int(y). If y is not in the range [-32767,
32767], the stored value is unspecified.

Possible implementation¶

constexpr std::chrono::year operator ""y(unsigned long long y) noexcept
{
return std::chrono::year(static_cast<int>(y));
}

Notes¶

This operator is declared in the namespace std::literals::chrono_literals, where
both literals and chrono_literals are inline namespaces. Access to this operator can
be gained with using namespace std::literals, using namespace std::chrono_literals,
and using namespace std::literals::chrono_literals.

In addition, within the namespace std::chrono, the directive using namespace
literals::chrono_literals; is provided by the standard library, so that if a
programmer uses using namespace std::chrono; to gain access to the classes in the
chrono library, the corresponding literal operators become visible as well.

Example¶

// Run this code

#include <iostream>
#include <chrono>

int main()
{
using namespace std::literals;

std::cout
<< int(2020y) << ' '
<< int(-220y) << ' '
<< int(3000y) << ' '
<< int(32768y) << ' ' // unspecified
<< int(65578y) << '\n'; // unspecified
}

Possible output:¶

2020 -220 3000 -32768 42

See also¶

constructor constructs a year
(public member function of std::chrono::year)