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std::is_bind_expression(3) C++ Standard Libary std::is_bind_expression(3)


std::is_bind_expression - std::is_bind_expression


Defined in header <functional>
template< class T > (since C++11)
struct is_bind_expression;

If T is the type produced by a call to std::bind, this template is derived from
std::true_type. For any other type, this template is derived from std::false_type.

This template may be specialized for a user-defined type T to implement
UnaryTypeTrait with base characteristic of std::true_type to indicate that T should
be treated by std::bind as if it were the type of a bind subexpression: when a
bind-generated function object is invoked, a bound argument of this type will be
invoked as a function object and will be given all the unbound arguments passed to
the bind-generated object.

Helper variable template

template< class T >
inline constexpr bool is_bind_expression_v = (since C++17)

Inherited from std::integral_constant

Member constants

value true if T is a function object generated by std::bind, false otherwise
[static] (public static member constant)

Member functions

operator bool converts the object to bool, returns value
(public member function)
operator() returns value
(C++14) (public member function)

Member types

Type Definition
value_type bool
type std::integral_constant<bool, value>


// Run this code

#include <iostream>
#include <type_traits>
#include <functional>

struct MyBind {
typedef int result_type;
int operator()(int a, int b) const { return a + b; }

namespace std {
struct is_bind_expression<MyBind> : public true_type {};

int f(int n1, int n2)
return n1+n2;

int main()
// as if bind(f, bind(MyBind(), _1, _2), 2)
auto b = std::bind(f, MyBind(), 2);

std::cout << "Adding 2 to the sum of 10 and 11 gives " << b(10, 11) << '\n';


Adding 2 to the sum of 10 and 11 gives 23

See also

bind binds one or more arguments to a function object
(C++11) (function template)