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std::experimental::propagate_const::operator=(3) C++ Standard Libary std::experimental::propagate_const::operator=(3)

NAME

std::experimental::propagate_const::operator= - std::experimental::propagate_const::operator=

Synopsis


constexpr propagate_const& operator=( (1) (library fundamentals TS v2)
propagate_const&& p ) = default;
template< class U >
constexpr propagate_const& operator=( (2) (library fundamentals TS v2)
propagate_const<U>&& pu );
template< class U > (3) (library fundamentals TS v2)
constexpr propagate_const& operator=( U&& u );
propagate_const& operator=( const propagate_const& (4) (library fundamentals TS v2)
) = delete;


Let t_ designate the private data member that is the wrapped pointer-like object.


1) Explicitly defaulted move assignment operator that move assigns this->t_ from
p.t_.
2) Assigns std::move(pu.t_) to this->t_.
This overload participates in overload resolution only if U is implicitly
convertible to T.
3) Assigns std::forward<U>(u) to this->t_.
This overload participates in overload resolution only if U is implicitly
convertible to T and std::decay_t<U> is not a specialization of propagate_const.
4) Copy assignment operator is explicitly deleted. propagate_const is non-copyable.

Parameters


p - another propagate_const object to move from
pu - another propagate_const object of a different specialization to move from
u - another object to assign to the contained pointer

Return value


*this.

2024.06.10 http://cppreference.com