std::chrono::year_month_weekday_last::operator+=,(3) | C++ Standard Libary | std::chrono::year_month_weekday_last::operator+=,(3) |
NAME¶
std::chrono::year_month_weekday_last::operator+=, - std::chrono::year_month_weekday_last::operator+=,
Synopsis¶
constexpr std::chrono::year_month_weekday_last& (1)
(since C++20)
operator+=( const std::chrono::years& dy ) const noexcept;
constexpr std::chrono::year_month_weekday_last& (2) (since
C++20)
operator+=( const std::chrono::months& dm ) const noexcept;
constexpr std::chrono::year_month_weekday_last& (3) (since
C++20)
operator-=( const std::chrono::years& dy ) const noexcept;
constexpr std::chrono::year_month_weekday_last& (4) (since
C++20)
operator-=( const std::chrono::months& dm ) const noexcept;
Modifies the time point *this represents by the duration dy or dm.
1) Equivalent to *this = *this + dy;
2) Equivalent to *this = *this + dm;
3) Equivalent to *this = *this - dy;
4) Equivalent to *this = *this - dm;
For durations that are convertible to both std::chrono::years and
std::chrono::months, the years overloads (1,3) are preferred if the call
would
otherwise be ambiguous.
Example¶
// Run this code
#include <iostream>
#include <chrono>
using namespace std::chrono;
int main()
{
std::cout << std::boolalpha;
auto ymwdl {August/Tuesday[last]/2022};
ymwdl += months(2);
std::cout << (year_month_day{ymwdl} == October/25/2022) << ' ';
ymwdl -= years(1);
std::cout << (year_month_day{ymwdl} == October/26/2021) << '\n';
}
Output:¶
true true
See also¶
operator+ adds or subtracts a year_month_weekday_last and some
number of years or
operator- months
(C++20) (function)
2022.07.31 | http://cppreference.com |