NAME¶

std::chrono::year_month_weekday_last::operator+=, - std::chrono::year_month_weekday_last::operator+=,

Synopsis¶

constexpr std::chrono::year_month_weekday_last& (1) (since C++20)
operator+=( const std::chrono::years& dy ) const noexcept;
constexpr std::chrono::year_month_weekday_last& (2) (since C++20)
operator+=( const std::chrono::months& dm ) const noexcept;
constexpr std::chrono::year_month_weekday_last& (3) (since C++20)
operator-=( const std::chrono::years& dy ) const noexcept;
constexpr std::chrono::year_month_weekday_last& (4) (since C++20)
operator-=( const std::chrono::months& dm ) const noexcept;

Modifies the time point *this represents by the duration dy or dm.

1) Equivalent to *this = *this + dy;.
2) Equivalent to *this = *this + dm;.
3) Equivalent to *this = *this - dy;.
4) Equivalent to *this = *this - dm;.

For durations that are convertible to both std::chrono::years and
std::chrono::months, the years overloads (1,3) are preferred if the call would
otherwise be ambiguous.

Example¶

// Run this code

#include <chrono>
#include <iostream>
using namespace std::chrono;

int main()
{
auto ymwdl{August/Friday[last]/2022};
std::cout << year_month_day{ymwdl} << '\n';
ymwdl += months(2);
std::cout << year_month_day{ymwdl} << '\n';
ymwdl -= years(1);
std::cout << year_month_day{ymwdl} << '\n';
}

Output:¶

2022-08-26
2022-10-28
2021-10-29

See also¶

operator+ adds or subtracts a year_month_weekday_last and some number of years or
operator- months
(C++20) (function)