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std::chrono::year_month_day_last::operator+=,std::chrono::year_month_day_last::operator-=(3) C++ Standard Libary std::chrono::year_month_day_last::operator+=,std::chrono::year_month_day_last::operator-=(3)

NAME

std::chrono::year_month_day_last::operator+=,std::chrono::year_month_day_last::operator-= - std::chrono::year_month_day_last::operator+=,std::chrono::year_month_day_last::operator-=

Synopsis


constexpr std::chrono::year_month_day_last& (1) (since C++20)
operator+=( const std::chrono::years& dy ) const noexcept;
constexpr std::chrono::year_month_day_last& (2) (since C++20)
operator+=( const std::chrono::months& dm ) const noexcept;
constexpr std::chrono::year_month_day_last& (3) (since C++20)
operator-=( const std::chrono::years& dy ) const noexcept;
constexpr std::chrono::year_month_day_last& (4) (since C++20)
operator-=( const std::chrono::months& dm ) const noexcept;


Modifies the time point *this represents by the duration dy or dm.


1) Equivalent to *this = *this + dy;
2) Equivalent to *this = *this + dm;
3) Equivalent to *this = *this - dy;
4) Equivalent to *this = *this - dm;


For durations that are convertible to both std::chrono::years and
std::chrono::months, the years overloads (1,3) are preferred if the call would
otherwise be ambiguous.

Example

// Run this code


#include <iostream>
#include <chrono>


int main()
{
std::cout << std::boolalpha;


auto ymdl {11/std::chrono::last/2020};
ymdl += std::chrono::years(15);
std::cout << (ymdl.day() == std::chrono::day(30)) << ' '
<< (ymdl.month() == std::chrono::November) << ' '
<< (ymdl.year() == std::chrono::year(2035)) << ' ';
ymdl -= std::chrono::months(6);
std::cout << (ymdl.day() == std::chrono::day(31)) << ' '
<< (ymdl.month() == std::chrono::May) << ' '
<< (ymdl.year() == std::chrono::year(2035)) << '\n';
}

Output:


true true true true true true

See also


operator+ adds or subtracts a year_month_day_last and some number of years or months
operator- (function)
(C++20)

2022.07.31 http://cppreference.com