std::chrono::year::operator+=,std::chrono::year::operator-=(3) | C++ Standard Libary | std::chrono::year::operator+=,std::chrono::year::operator-=(3) |
NAME¶
std::chrono::year::operator+=,std::chrono::year::operator-= - std::chrono::year::operator+=,std::chrono::year::operator-=
Synopsis¶
constexpr std::chrono::year& operator+=( const
std::chrono::years& (1) (since C++20)
y ) noexcept;
constexpr std::chrono::year& operator-=( const std::chrono::years&
(2) (since C++20)
y ) noexcept;
Adds or subtracts y.count() years from the year value.
1) Equivalent to *this = *this + y;.
2) Equivalent to *this = *this - y;.
Return value¶
A reference to this year after modification.
Notes¶
If the result would be outside the range [-32767, 32767], the
actual stored value is
unspecified.
Example¶
// Run this code
#include <chrono>
#include <iostream>
int main()
{
using namespace std::literals::chrono_literals;
std::cout << std::boolalpha;
std::chrono::year y{2020};
y += std::chrono::years(12);
std::cout << (y == 2032y) << ' ';
y -= std::chrono::years(33);
std::cout << (y == 1999y) << '\n';
}
Output:¶
true true
See also¶
operator++
operator++(int) increments or decrements the year
operator-- (public member function)
operator--(int)
operator+ performs arithmetic on years
operator- (function)
(C++20)
2024.06.10 | http://cppreference.com |