NAME¶

std::chrono::year::operator++,std::chrono::year::operator-- - std::chrono::year::operator++,std::chrono::year::operator--

Synopsis¶

constexpr std::chrono::year& operator++() noexcept; (1) (since C++20)
constexpr std::chrono::year operator++(int) noexcept; (2) (since C++20)
constexpr std::chrono::year& operator--() noexcept; (3) (since C++20)
constexpr std::chrono::year operator--(int) noexcept; (4) (since C++20)

Adds or subtracts 1 from the year value.

1-2) Performs *this += std::chrono::years{1};
3-4) Performs *this -= std::chrono::years{1};

Parameters¶

(none)

Return value¶

1,3) a reference to this year after modification
2,4) a copy of the year made before modification

Notes¶

If the result would be outside the range [-32767, 32767], the actual stored value is
unspecified.

Example¶

// Run this code

#include <iostream>
#include <chrono>

int main()
{
std::cout << std::boolalpha;

std::chrono::year y {2020};
std::cout << (++y == std::chrono::year(2021)) << ' ';
std::cout << (--y == std::chrono::year(2020)) << '\n';

using namespace std::literals::chrono_literals;
y = 32767y;
y++; //< unspecified, see Notes
std::cout << static_cast<int>(y) << '\n';
}

Possible output:¶

true true
-32768

See also¶

operator+= adds or subtracts a number of years from a year
operator-= (public member function)
operator+ performs arithmetic on years
operator- (function)
(C++20)