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std::chrono::weekday_last::weekday_last(3) C++ Standard Libary std::chrono::weekday_last::weekday_last(3)

NAME

std::chrono::weekday_last::weekday_last - std::chrono::weekday_last::weekday_last

Synopsis


explicit constexpr weekday_last( const std::chrono::weekday& wd ) (since C++20)
noexcept;


Constructs a weekday_last object storing the weekday wd.

Notes


A more convenient way to construct a weekday_last is with weekday's operator[],
i.e., wd[std::chrono::last].

Example

// Run this code


#include <chrono>
#include <iostream>
using namespace std::chrono;


int main() {
const year_month_day ymd { floor<days>(system_clock::now()) };
const weekday_last wdl { Sunday[last] }; // A last Sunday of a month
const year_month_day last_sun { ymd.year() / ymd.month() / wdl };


std::cout << "The last Sunday of current month falls on "
<< (int)last_sun.year() << '/'
<< (unsigned)last_sun.month() << '/'
<< (unsigned)last_sun.day() << '\n';
}

Possible output:


The last Sunday of current month falls on 2021/9/26

2022.07.31 http://cppreference.com