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std::adjacent_find(3) C++ Standard Libary std::adjacent_find(3)

NAME

std::adjacent_find - std::adjacent_find

Synopsis


Defined in header <algorithm>
template< class ForwardIt >
ForwardIt adjacent_find( ForwardIt first, ForwardIt last (1) (constexpr since C++20)
);
template< class ExecutionPolicy, class ForwardIt >


ForwardIt adjacent_find( ExecutionPolicy&& policy, (2) (since C++17)


ForwardIt first, ForwardIt last
);
template< class ForwardIt, class BinaryPred >


ForwardIt adjacent_find( ForwardIt first, ForwardIt (3) (constexpr since C++20)
last,


BinaryPred p );
template< class ExecutionPolicy, class ForwardIt, class
BinaryPred >


ForwardIt adjacent_find( ExecutionPolicy&& policy, (4) (since C++17)
ForwardIt first, ForwardIt
last,


BinaryPred p );


Searches the range [first, last) for two consecutive equal elements.


1) Elements are compared using operator==.
3) Elements are compared using the given binary predicate p.
2,4) Same as (1,3), but executed according to policy.
These overloads participate in overload resolution only if


std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true. (until
C++20)
std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>> is true. (since
C++20)

Parameters


first, last - the range of elements to examine
policy - the execution policy to use. See execution policy for details.
binary predicate which returns true if the elements should be treated
as equal.


The signature of the predicate function should be equivalent to the
following:


bool pred(const Type1 &a, const Type2 &b);


p - While the signature does not need to have const &, the function must
not modify the objects passed to it and must be able to accept all
values of type (possibly const) Type1 and Type2 regardless of value
category (thus, Type1 & is not allowed
, nor is Type1 unless for Type1 a move is equivalent to a copy
(since C++11)).
The types Type1 and Type2 must be such that an object of type
ForwardIt can be dereferenced and then implicitly converted to both of
them.

Type requirements


-
ForwardIt must meet the requirements of LegacyForwardIterator.
-
BinaryPred must meet the requirements of BinaryPredicate.

Return value


An iterator to the first of the first pair of identical elements, that is, the first
iterator it such that *it == *(it + 1) for (1,2) or p(*it, *(it + 1)) != false for
(3,4).


If no such elements are found, last is returned.

Complexity


Given result as the return value of adjacent_find, \(\scriptsize M\)M as
std::distance(first, result) and \(\scriptsize N\)N as std::distance(first, last):


1) Exactly \(\scriptsize \min(M+1,N-1)\)min(M+1,N-1) comparisons using operator==.
2) \(\scriptsize O(N)\)O(N) comparisons using operator==.
3) Exactly \(\scriptsize \min(M+1,N-1)\)min(M+1,N-1) applications of the predicate
p.
4) \(\scriptsize O(N)\)O(N) applications of the predicate p.

Exceptions


The overloads with a template parameter named ExecutionPolicy report errors as
follows:


* If execution of a function invoked as part of the algorithm throws an exception
and ExecutionPolicy is one of the standard policies, std::terminate is called.
For any other ExecutionPolicy, the behavior is implementation-defined.
* If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Possible implementation


adjacent_find (1)
template<class ForwardIt>
ForwardIt adjacent_find(ForwardIt first, ForwardIt last)
{
if (first == last)
return last;


ForwardIt next = first;
++next;


for (; next != last; ++next, ++first)
if (*first == *next)
return first;


return last;
}
adjacent_find (3)
template<class ForwardIt, class BinaryPred>
ForwardIt adjacent_find(ForwardIt first, ForwardIt last, BinaryPred p)
{
if (first == last)
return last;


ForwardIt next = first;
++next;


for (; next != last; ++next, ++first)
if (p(*first, *next))
return first;


return last;
}

Example

// Run this code


#include <algorithm>
#include <functional>
#include <iostream>
#include <vector>


int main()
{
std::vector<int> v1{0, 1, 2, 3, 40, 40, 41, 41, 5};


auto i1 = std::adjacent_find(v1.begin(), v1.end());


if (i1 == v1.end())
std::cout << "No matching adjacent elements\n";
else
std::cout << "The first adjacent pair of equal elements is at "
<< std::distance(v1.begin(), i1) << ", *i1 = "
<< *i1 << '\n';


auto i2 = std::adjacent_find(v1.begin(), v1.end(), std::greater<int>());
if (i2 == v1.end())
std::cout << "The entire vector is sorted in ascending order\n";
else
std::cout << "The last element in the non-decreasing subsequence is at "
<< std::distance(v1.begin(), i2) << ", *i2 = " << *i2 << '\n';
}

Output:


The first adjacent pair of equal elements is at 4, *i1 = 40
The last element in the non-decreasing subsequence is at 7, *i2 = 41


Defect reports


The following behavior-changing defect reports were applied retroactively to
previously published C++ standards.


DR Applied to Behavior as published Correct behavior
the predicate was applied std::find applied std::min(
LWG 240 C++98 (first, last, value) - first times (result - first) + 1,
for (1,3), where value was never (last - first) - 1) times
defined

See also


unique removes consecutive duplicate elements in a range
(function template)
ranges::adjacent_find finds the first two adjacent items that are equal (or satisfy
(C++20) a given predicate)
(niebloid)

2024.06.10 http://cppreference.com