| std::chrono::operator+,std::chrono::operator-(std::chrono::year_month_day)(3) | C++ Standard Libary | std::chrono::operator+,std::chrono::operator-(std::chrono::year_month_day)(3) | 
NAME¶
std::chrono::operator+,std::chrono::operator-(std::chrono::year_month_day) - std::chrono::operator+,std::chrono::operator-(std::chrono::year_month_day)
Synopsis¶
 Defined in header <chrono>
  
   constexpr std::chrono::year_month_day operator+( const
  
   std::chrono::year_month_day& ymd,
  
   (since C++20)
  
   const std::chrono::months& dm
  
   ) noexcept;
  
   constexpr std::chrono::year_month_day operator+( const
  
   std::chrono::months& dm,
  
   (since C++20)
  
   const std::chrono::year_month_day& ymd
  
   ) noexcept;
  
   constexpr std::chrono::year_month_day operator+( const
  
   std::chrono::year_month_day& ymd,
  
   (since C++20)
  
   const std::chrono::years& dy
  
   ) noexcept;
  
   constexpr std::chrono::year_month_day operator+( const
  
   std::chrono::years& dy,
  
   (since C++20)
  
   const std::chrono::year_month_day& ymd
  
   ) noexcept;
  
   constexpr std::chrono::year_month_day operator-( const
  
   std::chrono::year_month_day& ymd,
  
   (since C++20)
  
   const std::chrono::months& dm
  
   ) noexcept;
  
   constexpr std::chrono::year_month_day operator-( const
  
   std::chrono::year_month_day& ymd,
  
   (since C++20)
  
   const std::chrono::years& dy
  
   ) noexcept;
  
   1-2) Adds dm.count() months to the date represented by ymd. The result has
    the same
  
   day() as ymd and the same year() and month() as
    std::chrono::year_month(ymd.year(),
  
   ymd.month()) + dm.
  
   3-4) Adds dy.count() years to the date represented by ymd. The result is
    equivalent
  
   to std::chrono::year_month_day(ymd.year() + dy, ymd.month(), ymd.day().
  
   5) Subtracts dm.count() months from the date represented by ymd. Equivalent
    to ymd +
  
   -dm.
  
   6) Subtracts dy.count() years from the date represented by ymd. Equivalent to
    ymd +
  
   -dy.
  
   For durations that are convertible to both std::chrono::years and
  
   std::chrono::months, the years overloads (3,4,6) are preferred if the call
    would
  
   otherwise be ambiguous.
Notes¶
 Even if ymd.ok() is true, the resulting year_month_day may not
    represent a valid
  
   date if ymd.day() is 29, 30, or 31.
Example¶
// Run this code
  
   #include <iostream>
  
   #include <chrono>
  
   int main()
  
   {
  
   std::cout << std::boolalpha;
  
   auto ymd {std::chrono::day(1)/std::chrono::July/2021};
  
   ymd = ymd + std::chrono::months(4);
  
   std::cout << (ymd.month() == std::chrono::November) << ' '
  
   << (ymd.year() == std::chrono::year(2021)) << ' ';
  
   ymd = ymd - std::chrono::years(10);
  
   std::cout << (ymd.month() == std::chrono::month(11)) << ' '
  
   << (ymd.year() == std::chrono::year(2011)) << ' ';
  
   }
Output:¶
true true true true
| 2022.07.31 | http://cppreference.com |